SOLUTION: the volume V of a given mass of a gas varies directly as the temperature T and inversely as the pressure P. If V=231cm^3 when T=300 degrees K (Kelvin) and P=20lb/cm^2, what is the

Algebra ->  Functions -> SOLUTION: the volume V of a given mass of a gas varies directly as the temperature T and inversely as the pressure P. If V=231cm^3 when T=300 degrees K (Kelvin) and P=20lb/cm^2, what is the       Log On


   

Question 1048891: the volume V of a given mass of a gas varies directly as the temperature T and inversely as the pressure P. If V=231cm^3 when T=300 degrees K (Kelvin) and P=20lb/cm^2, what is the volume when T=320 degrees K and P=16 lb/cm^2?
Answer by Alan3354(69443) About Me  (Show Source):
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the volume V of a given mass of a gas varies directly as the temperature T and inversely as the pressure P. If V=231cm^3 when T=300 degrees K (Kelvin) and P=20lb/cm^2, what is the volume when T=320 degrees K and P=16 lb/cm^2?
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PV = nRT
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P*V = k*t
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You can solve for k, then solve the problem, or solve it as a proportion.
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P*V = k*T
20*231 = k*300
k = 20*231/300 = 15.4
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P*V = k*T = 15.4T
V = 15.4T/P = 15.4*320/16
V = 308 cubic cm