SOLUTION: I am having trouble with my math question. My problem is "what is the perimiter and area of a rectangle with the length of (x+3) and (x-7)"

Algebra ->  Rectangles -> SOLUTION: I am having trouble with my math question. My problem is "what is the perimiter and area of a rectangle with the length of (x+3) and (x-7)"      Log On


   



Question 1048751: I am having trouble with my math question. My problem is "what is the perimiter and area of a rectangle with the length of (x+3) and (x-7)"
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Length = +x+%2B+3+
Width = +x+-+7+
Let the perimeter = +P+
Let the area = +A+
----------------------
The formula for perimeter is:
[ twice the length ] + [ twice the width ] = [ perimeter ]
+P+=+2%2A%28+x%2B3+%29+%2B+2%2A%28+x+-7+%29+
+P+=+2x+%2B+6+%2B+2x+-+14+
+P+=+4x+-+8+
-----------------
The formula for area is:
[ length ] x [ width ] = [ area ]
+A+=+%28+x+%2B+3+%29%2A%28+x+-+7+%29+
+A+=+x%5E2+%2B+3x+-+7x+-+21+
+A+=+x%5E2+-+4x+-+21+