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Find the equation (y=mx+c) of the tangent line to the graph of the function f at the point (1,15). f(x)=3x^(2)-1
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Find the equation (y=mx+c) of the tangent line to the graph of the function f at the point (1,15). f(x)=3x^(2)-1
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Question 1048714: Please help solve and provide workings for this question, thanks.
Find the equation (y=mx+c) of the tangent line to the graph of the function f at the point (1,15). f(x)=3x^(2)-11x+23 Answer by Alan3354(69443) (Show Source):
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Find the equation (y=mx+c) of the tangent line to the graph of the function f at the point (1,15). f(x)=3x^(2)-11x+23
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f(x) = 3x^2 - 11x + 23
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Do you know how to find the 1st derivative?
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Is this a calculus class? or earlier?
