LCD = (x-5)(x+1)2
Now we analyze the polynomial
candidates for zeros are ±1, ±2, ±13, ±26
We begin by trying +1 using synthetic division with
the factor theorem:
1|1 5 20 -26
| 1 6 26
1 6 26 0
That was fortunate. The very first candidate for a
zero succeeded!
So
factors as
The quadratic does not factor, so the final result is:
Edwin