SOLUTION: A passenger plane flew to Jakarta and back. It took one hour longer to go there than it did to come back. Let t represent the time it took to fly back. The average speed on the tri

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Question 1048576: A passenger plane flew to Jakarta and back. It took one hour longer to go there than it did to come back. Let t represent the time it took to fly back. The average speed on the trip there was 180mi/h. The average speed on the way back was 200m/h. How many hours did each trip take?
Tried:
180(t+1)=200t
180t+180=200t
180=20t
t=90
Is this correct?

Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Time t is in hours. Distance each way d, is also unknown as is t.
                   RATE           TIME        DISTANCE

TRIP THERE         180            t+1           d

RETURNING          200            t             d

system%28180%2A%28t%2B1%29=d%2C200t=d%29

180%28t%2B1%29=200t
180t%2B180=200t
180=20t
t=180%2F20=18%2F2
You just made a decimal mistake.


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Another way of showing that you know what you need to do to solve this problem, but as sometimes happens, a computational mistake occurs. Mistake NOT because of lack of understanding - just a slippage in attention.