SOLUTION: ABC is a right angled triangle.
Right angled at A.P is a length from A perpendicular to BC.
Show that:-
(a) PA=BC
(b) 1/square of small a= 1/square of small b+1/square of c
Algebra ->
Pythagorean-theorem
-> SOLUTION: ABC is a right angled triangle.
Right angled at A.P is a length from A perpendicular to BC.
Show that:-
(a) PA=BC
(b) 1/square of small a= 1/square of small b+1/square of c
Log On
Question 1048385: ABC is a right angled triangle.
Right angled at A.P is a length from A perpendicular to BC.
Show that:-
(a) PA=BC
(b) 1/square of small a= 1/square of small b+1/square of c
