SOLUTION: Jim needed to do laundry and had a total of $5.15 in his coin jar. The only problem was that the laundromat only accepted quarters. He had quarters and dimes in the jar. Jim had 8

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: Jim needed to do laundry and had a total of $5.15 in his coin jar. The only problem was that the laundromat only accepted quarters. He had quarters and dimes in the jar. Jim had 8       Log On

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Question 1048326: Jim needed to do laundry and had a total of $5.15 in his coin jar. The only problem was that the laundromat only accepted quarters. He had quarters and dimes in the jar. Jim had 8 less dimes than he had quarters, so he must have had ? Quarters and ? Dimes
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
Goal first is find the combination of coins Jim has.

system%280.1d%2B0.25q=5.15%2Cd=q-8%29

Multiply the money count by 20, on both MEMBERS and substitute for d.