SOLUTION: a web developer is creating a website. The page will have a frame along its top and left sides showing the name of the site and links to different parts of the site. These frames

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Question 1048322: a web developer is creating a website. The page will have a frame along its top and left sides showing the name of the site and links to different parts of the site. These frames will take up one third of the computer screen. If the computer screen is 7 in by 11 in, what will the width of the frames be?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
If the frames take up 1/3 of the screen,
then the page itself takes up 2/3 of
the screen
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Let +x+ = the width of the frames
+%28+7+-+2x+%29%2A%28+11+-+2x+%29+=+%282%2F3%29%2A7%2A11+
+3%2A%28+77+-+22x+-+14x+%2B+4x%5E2+%29+=+154+
+231+-+108x+%2B+12x%5E2+=+154+
+12x%5E2+-+108x+%2B+77+=+0+
Solve using quadratic formula
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
+a+=+12+
+b+=+-108+
+c+=+77+
x+=+%28-%28-108%29+%2B-+sqrt%28+%28-108%29%5E2-4%2A12%2A77+%29%29%2F%282%2A12%29+
x+=+%28+108+%2B-+sqrt%28+11664+-+3696+%29%29%2F24+
+x+=+%28+108+-+sqrt%28+7968+%29+%29+%2F+24+
+x+=+%28+108+-+89.264+%29+%2F+24+
+x+=+18.736%2F24+
+x+=+.78067+
The width of the frames is .78067 inches
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check:
+%28+7+-+2x+%29%2A%28+11+-+2x+%29+=+%282%2F3%29%2A7%2A11+
+%28+7+-+2%2A.78067+%29%2A%28+11+-+2%2A.78067+%29+=+%282%2F3%29%2A7%2A11+
+%28+7+-+1.56134+%29%2A%28+11+-+1.56134+%29+=+154%2F3+
+5.43866%2A9.43866+=+51.333+
+51.334+=+51.333+
close enough -hope I got it!