SOLUTION: A bag contains 10 red marbles,7 green marbles,9 black marbles. If one marble is drawn from the bag but not replaced, what is the probability of drawing a
red marble then a black
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-> SOLUTION: A bag contains 10 red marbles,7 green marbles,9 black marbles. If one marble is drawn from the bag but not replaced, what is the probability of drawing a
red marble then a black
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Question 1048291: A bag contains 10 red marbles,7 green marbles,9 black marbles. If one marble is drawn from the bag but not replaced, what is the probability of drawing a
red marble then a black marble? Answer by jorel555(1290) (Show Source):
You can put this solution on YOUR website! The probability of drawing a red marble first is 10/(10+7+9), or 10/26. Drawing a black marble second would be 9/25. So the combined probability of drawing a red first and black second is:
10/26 x 9/25=90/650, or 9/65. ☺☺☺☺
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