SOLUTION: How many pounds of candy that sells for ​$0.82 per lb must be mixed with candy that sells for ​$1.36 per lb to obtain 8 lb of a mixture that should sell for ​$0.9

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: How many pounds of candy that sells for ​$0.82 per lb must be mixed with candy that sells for ​$1.36 per lb to obtain 8 lb of a mixture that should sell for ​$0.9      Log On


   

Question 1048280: How many pounds of candy that sells for ​$0.82 per lb must be mixed with candy that sells for ​$1.36 per lb to obtain 8 lb of a mixture that should sell for ​$0.97 per​ lb?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
Set UP
MIX
1.36x + .82(8lb-x) = .97(8lb)
.54x = .15(8lb)
x = .15(8lb)/.54