SOLUTION: the coordinates of the vertices of a triangle are P(-2;6),Q(x;2) and R(-8;a). find the value of x if the distance of PQ equals √80
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Question 1048226: the coordinates of the vertices of a triangle are P(-2;6),Q(x;2) and R(-8;a). find the value of x if the distance of PQ equals √80 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! the coordinates of the vertices of a triangle are P(-2;6),Q(x;2) and R(-8;a). find the value of x if the distance of PQ equals √80
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(x+2)^2 + (6-2)^2 = 80
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x^2 + 4x + 4 + 16 = 80
x^2 + 4x - 60 = 0
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(x+10)(x-6) = 0
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x = 6 or x = -10
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Cheers,
Stan H.
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