SOLUTION: A car and a bus start at 8:00am from the same point and travel in the same direction. The average speed of the car is 60mph. In 2 hours the car is 30 miles ahead of the bus. Find

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Question 1048146: A car and a bus start at 8:00am from the same point and travel in the same direction. The average speed of the car is 60mph. In 2 hours the car is 30 miles ahead of the bus. Find the average speed of the bus.
Found 3 solutions by josgarithmetic, ikleyn, advanced_Learner:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
RT=D, constant travel rate rule 

                SPEED        TIME        DISTANCE
CAR             60            2           d+30
BUS             r             2           d

Both d and r are unknown, and you can solve for both.


%2860%29%282%29=d%2B30
d=60%2A2-30
highlight_green%28d=90%29


%28r%29%282%29=d
r=d%2F2
r=90%2F2
highlight%28r=45%29---------answer to the question

Answer by ikleyn(52921) About Me  (Show Source):
You can put this solution on YOUR website!
.
A car and a bus start at 8:00 am from the same point and travel in the same direction. The average speed of the car is 60 mph.
In 2 hours the car is 30 miles ahead of the bus. Find the average speed of the bus.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

In 2 hours the car traveled 2*60 = 120 miles.

At that time the bus was 30 miles behind the car. Hence, the bus covered only 120-30 = 90 miles in 2 hours.

Hence, the bus' average speed was 90%2F2 = 45 miles per hour.

The problem is solved in 3 (three) lines and without any equations.

You only need to think.


Answer by advanced_Learner(501) About Me  (Show Source):
You can put this solution on YOUR website!
60*2-2*S=30
s=45

in two hours car travels 120 miles
in two hours the bus travels 90 miles
so difference is 30 miles.