Question 1048011: the problem says to find Y i will try to illustrate it as best I can i have drawn the picture but it will not paste
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/30|40\
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/ | \
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/80 x | \
/ |y z\
/_________________\_ when i preview the question all the lines in the illustration move to the left so i will try to explain it the vertical line separates the two triangle in the left triangle at the top you have 30 degrees in the bottom left you have 80 degrees and on the bottom right of the left triangle you have x, in the right triangle at the top you have 40 degrees on the bottom left of the right triangle you have y and on the bottom right of the right triangle you have z i hope the explanation helps
Found 2 solutions by Alan3354, Theo:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! the problem says to find Y i will try to illustrate it as best I can i have drawn the picture but it will not paste
/|\
/ | \
/30|40\
/ | \
/ | \
/ | \
/80 x | \
/ |y z\
/_________________\_ when i preview the question all the lines in the illustration move to the left so i will try to explain it the vertical line separates the two triangle in the left triangle at the top you have 30 degrees in the bottom left you have 80 degrees and on the bottom right of the left triangle you have x, in the right triangle at the top you have 40 degrees on the bottom left of the right triangle you have y and on the bottom right of the right triangle you have z
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If y is the length:
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1st find x.
cos(30) = x/80
x = 80*sqrt(3)/2 = 40sqrt(3)
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tan(40) = y/x
y = tan(40)*40sqrt(3)
y =~ 58.135
Answer by Theo(13342)  (Show Source):
You can put this solution on YOUR website! if you use pre on the first line before the diagram and /pre on the last line after the diagram, they should stay spaced out the way you want them.
you need, however, to surround pre with <> and you need to surround /pre with <>
i took your diagram and used pre and /pre surrounded by <> and this is what i was able to get.
/|\
/ | \
/30|40\
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/ | \
/80 x|y z\
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here's a picture of how the inputs would look.
in the triangle on the left, angle x has to be 70 degrees because the sum of the angles of a triangle are 180 degrees.
angle y is supplementary to angle x and is there equal to 180 - 70 = 110 degrees.
z has to be equal to 30 degrees because the sum of the angles of a triangle have to be 180 degrees and 110 + 40 + 30 = 180.
the diagram is, of course, not drawn to scale.
if it was drawn to scale, it would look more like this:
if i am correct, than your solution should be that y is equal to 110 degrees.
try that and see if it works.
let me know how you did.
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