SOLUTION: On a 3 positive consecutive integer the middle number is p. If 3 times the square of the largest number is greater than the sum of the other2 number by 67 find the value of p

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: On a 3 positive consecutive integer the middle number is p. If 3 times the square of the largest number is greater than the sum of the other2 number by 67 find the value of p       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1047994: On a 3 positive consecutive integer the middle number is p. If 3 times the square of the largest number is greater than the sum of the other2 number by 67 find the value of p
Found 2 solutions by Horlaye, ikleyn:
Answer by Horlaye(27) About Me  (Show Source):
You can put this solution on YOUR website!
Let the numbers be p-1, p, p+1
from the sentence
3(p+1) - (p-1+p) = 67
3p + 3 - p + 1 - p = 67
p = 67 - 4
p = 63

Answer by ikleyn(52914) About Me  (Show Source):
You can put this solution on YOUR website!
.
On a 3 positive consecutive integer the middle number is p. If 3 times the square of the largest number is greater
than the sum of the other 2 number by 67 find the value of p
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

So, the numbers are p-1, p, and p+1.
The condition says

3%2A%28p%2B1%29%5E2 - ((p-1) + p) = 67.

Simplify

3p%5E2+%2B+6p+%2B+3+-+p+%2B+1+-+p = 67,

3p%5E2+%2B+4p+%2B+4 = 67,

3p%5E2+%2B+4p+-+63 = 0.

There is no solution in integer numbers.

Answer. There is no solution in integer numbers.