SOLUTION: Is this statement true or false and why? If {{{ f(x) = x + 1 }}} and {{{ g(x) = 6x }}} then (f ○ g){{{ (x) }}} = (g ○ f){{{ (x) }}}

Algebra ->  Expressions-with-variables -> SOLUTION: Is this statement true or false and why? If {{{ f(x) = x + 1 }}} and {{{ g(x) = 6x }}} then (f ○ g){{{ (x) }}} = (g ○ f){{{ (x) }}}       Log On


   

Question 1047932: Is this statement true or false and why?
If +f%28x%29+=+x+%2B+1+ and +g%28x%29+=+6x+ then (f ○ g)+%28x%29+ = (g ○ f)+%28x%29+
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
g%28f%28x%29%29=6%28f%28x%29%29
g%28f%28x%29%29=6%28x%2B1%29
g%28f%28x%29%29=6x%2B6


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Misunderstood.

The compositions are NOT equal.
f%28g%28x%29%29=%286x%2B1%29=6x%2B1


Question is, do these functions composed, f%28g%28x%29%29=g%28f%28x%29%29?
6x%2B1=6x%2B6 ?
NO. The equality is FALSE.