Question 1047914: A 26 ft piece of rope is cut into three pieces such that the second piece is twice the first piece and the third piece is 4ft less than 3 times the first piece. Find the length of the third piece
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A 26 ft piece of rope is cut into three pieces such that the second piece is twice the first piece and the third piece is 4ft less than 3 times the first piece. Find the length of the third piece
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Let the pieces be f,s,t (1st,2nd,3rd)
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Equations:
f + s + t = 26 ft
s = 2f
t = 3f-4
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Substitute to solve for "f"::
f + 2f + 3f-4 = 26
6f = 30
first = 5 ft
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Ans: third = t = 3f-4 = 11 ft
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Cheers,
Stan H.
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