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Question 1047791: If I don't get this ASAP, I'll be in big trouble. Can somebody please Help me?!
1. Write an equation of the line that passes through the point (3,0) and
has the slope, m = -2.
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2. Write an equation of the line that passes through the point (1,2) and
has the slope, m = 2.
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3. Write an equation in point-slope form of the line that passes through
the points (-5,-4) and (7,-5).
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4. Write the equation 5x - y + 6 = 0 in standard form with integer
coefficients.
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5. Write the equation y = -3x + 9 in standard form with integer
coefficients.
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THANK YOU!
Found 2 solutions by Boreal, ewatrrr:
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! 1. slope is -2 and through (3,0). Point slope formula, y-y1=m(x-x1)
y-0=-2(x-3)
y=-2x+6
2.y-2=2(x-1)
y-2=2x-2, distributing
y=2x
3.Need slope first, which is change in y over change in x. That is -9/12=-3/4
y+5=(-1/12)(x-7). You can use the other point if desired and watch the signs.
y+5=(-x/12)+(7/12);5=60/12
y=-(1/12)x-(53/12)
check with other point
y+4=(1/12)(x+5)
y+4=(1/12)x-(5/12)
y=(-1/12)x-(53/12)
4.Just move the 6 to the other side. That makes it standard form.
5x-y=-6. The coefficient of y is implied -1, an integer.
5.y=-3x+9 is slope-intercept form.
Move the x to the other side and you are done.
3x+y=9. This is standard form. The x and y have to have integer coefficients, and the x one must be positive. The constant is on the other side and has to be an integer.
Answer by ewatrrr(24785)  (Show Source):
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