SOLUTION: The area of a rectangular hall is 48 square metres. If the length and breadth be increased by 1 metre each the area is increased by 15 square metres. Find the length and breadth of

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: The area of a rectangular hall is 48 square metres. If the length and breadth be increased by 1 metre each the area is increased by 15 square metres. Find the length and breadth of      Log On


   



Question 1047748: The area of a rectangular hall is 48 square metres. If the length and breadth be increased by 1 metre each the area is increased by 15 square metres. Find the length and breadth of the hall.
Found 3 solutions by josgarithmetic, advanced_Learner, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x and y dimensions,
xy=48

Length is x and breadth is y.

If the length and breadth be increased by 1 metre each the area is increased by 15 square metres.
-
-
%28x%2B1%29%28y%2B1%29-xy=15
xy%2Bx%2By%2B1-xy=15
xy-xy%2Bx%2By=15
x%2By=15

Your system of two equations is now system%28xy=48%2Cx%2By=15%29, which you may already know how to solve.

Answer by advanced_Learner(501) About Me  (Show Source):
You can put this solution on YOUR website!
The area of a rectangular hall is 48 square metres. If the length and breadth be increased by 1 metre each the area is increased by 15 square metres. Find the length and breadth of the hall.
xy=48
(x+1)(y+1)=63
xy+x+y+1=63
48+x+y+1=63
49+x+y=63
x+y=63-49
x+y=14
-------------------------------------------------------------------------------==
xy=48
x+y=14
which gives answer x=6 and y =8
check
6*8 area is 48

let us increase area by 1
7*9=63 area is increased by 15

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

The area of a rectangular hall is 48 square metres. If the length and breadth be increased by 1 metre each the area is increased by 15 square metres. Find the length and breadth of the hall.
Let the original length be L
Then breadth = 48%2FL
We then get: %28L+%2B+1%29%2848%2FL+%2B+1%29+=+63
48+%2B+L+%2B+48%2FL+%2B+1+=+63
L+%2B+48%2FL+%2B+49+=+63
L+%2B+48%2FL+=+14
L%5E2+%2B+48+=+14L ------- Multiplying by LCD, L
L%5E2+-+14L+%2B+48+=+0
(L - 8)(L - 6) = 0
L, or original length = 8 m OR L = 6 m
If original length = 8 m, original breadth = 6 m
If original length = 6 m, original breadth = 8 m