SOLUTION: Two positive numbers are in the ratio 3: 4. Find the numbers if (a) their sum is 84 and (b) their product is 588.

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Two positive numbers are in the ratio 3: 4. Find the numbers if (a) their sum is 84 and (b) their product is 588.       Log On


   

Question 1047713: Two positive numbers are in the ratio 3: 4. Find the numbers if (a) their sum is 84 and (b) their product is 588.

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
;two number a & b
:
Two positive numbers are in the ratio 3: 4.
a%2Fb = 3%2F4
cross multiply
4a = 3b
a = 3%2F4b
a = .75b
:
Find the numbers if:
(a) their sum is 84
a + b = 84
replace a with .75b
.75b + b = 84
1.75b = 84
b = 84/1.75
b = 48
Find a
a = .75(48)
a = 36
and
(b) their product is 588.
a * b = 588
replace a with .75b
.75b^2 = 588
b^2 = 588/.75
b^2 = 784
b = sqrt%28784%29
b = 28
find a
a = .75(28)
a = 21
:
;
Check: 21 * 28 = 588