Question 1047404: Please help me with this question
Two dice are thrown
.draw a tree diagram
.What is the probability of obtaining two no. 4s
.a two and a five
.Obtaining only one two
.Not obtaining two threes landing face up
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website! (1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
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P(two no. 4s) = 1/36
P( two and a five) = P(2,5) + P(5,2) = 2/36 = 1/18
P(Obtaining only one two) = 5/36(2nd column - 2 second) + 5/36(2nd row - 2 first) = 10/36 = 5/18
P(Not obtaining two threes landing face up) = 1 - P(3,3) = 1-1/36 = 35/36
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