Question 1047366: i have a collection of nickels, dimes, and quarters in a money bag worth $16.85. If the number of quarters is two hundred thirty-seven less than three times the number of nickels and the number of dimes is one hundred sixty-nine less than twice the number of nickels, find the number of each type of coin.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! i have a collection of nickels, dimes, and quarters in a money bag worth $16.85. If the number of quarters is two hundred thirty-seven less than three times the number of nickels and the number of dimes is one hundred sixty-nine less than twice the number of nickels, find the number of each type of coin.
:
let n = no. of nickels
let d = no. of dimes
let = no. of quarters
:
"If the number of quarters is two hundred thirty-seven less than three times the number of nickels"
q = 3n-237
"and the number of dimes is one hundred sixty-nine less than twice the number of nickels"
d = n-169
:
.05n + .10d + .25q = 16.85
replace d and q
.05n + .10(2n-169) + .25(3n-237) = 16.85
.05n + .20n + .75n - 76.15 = 16.85
1.0n = 16.85 + 76.15
n = 93 nickels
find d
d = 2(93) - 169
d = 17 dimes
find q
q = 3(93) - 237
q = 42 quarters
:
;
see if this adds up
93(.05) = 4.65
17(.10) = 1.70
42(.25)= 10.50
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Total $: 16.85
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