SOLUTION: Given that logx2=0.3562 and logx3=0.5646. Using these values calculate the value of logx11. Note: x stands for the letter x not for multiplication. And the letter x is the

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Given that logx2=0.3562 and logx3=0.5646. Using these values calculate the value of logx11. Note: x stands for the letter x not for multiplication. And the letter x is the      Log On


   

Question 1047357: Given that logx2=0.3562 and logx3=0.5646. Using these values calculate the value of logx11.
Note: x stands for the letter x not for multiplication. And the letter x is the base of the log.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Given that logx2=0.3562 and logx3=0.5646. Using these values calculate the value of logx11.
Note: x stands for the letter x not for multiplication. And the letter x is the base of the log.
:
Find x
log%28x%2C2%29+=+.3562
The exponent equiv
x%5E.3562+=+2
x+=+2%5E%281%2F.3562%29
using a calc find the value of 2 with that exponent
x = 7
:
Check:
log%28x%2C3%29+=+.5646
Replace x with 7
log%287%2C3%29+=+.5646
using a calc
7^.5646 = 3
:
now we have
log%287%2C11%29+=+y
7%5Ey+=+11
using nat logs
y%2Aln%287%29+=+ln%2811%29
y = ln%2811%29%2Fln%287%29
using your calc
y = 1.2323
so we have
log%287%2C11%29+=+1.2323 is the solution
:
:
Check: 7%5E1.2323 = 11