SOLUTION: Please find the minimum and maximum values of the expression {{{sin^8(x)+cos^14(x)}}}.

Algebra ->  Trigonometry-basics -> SOLUTION: Please find the minimum and maximum values of the expression {{{sin^8(x)+cos^14(x)}}}.      Log On


   



Question 1047332: Please find the minimum and maximum values of the expression sin%5E8%28x%29%2Bcos%5E14%28x%29.
Found 3 solutions by josmiceli, robertb, ikleyn:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The maximum of both sin and cos function is +1+
So the maximum of the expression is +2+
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The even exponents make any negative value positive,
so the minimum has to be 0

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
Well, I am sending this commentary to "ikleyn"--
Of course, it will be "SLIGHTLY SHIFTED".
One MISTAKE you made was that you plotted z+=+w%5E7+%2B+%281-w%29%5E4 as if x was the independent variable in the function, and over the SAME COORDINATE SYSTEM! It was NOT.
Remember, I let w+=+cos%5E2%28x%29.
So naturally, the lowest points of the two graphs will NOT jive. BUT, what is guaranteed is that they will have the SAME LOWEST level.
Another MISTAKE you made was that, z is a composite function, and as such, its domain, as a function of w, is only 0+%3C=+w+%3C=+1. Meaning, your green-colored graph is WRONG.
The range of z is [,1], or[0.05310578625,1] (approximately).
In fact, I can even predict/estimate the amount of "shift" that you're talking about:
cos%5E-1%28sqrt%280.5860760201%29%29+-+0.5860760201+=+0.1128151882.

Naughty, naughty, not so smarty....

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sin%5E8%28x%29%2Bcos%5E14%28x%29
= %28sin%5E2%28x%29%29%5E4%2B%28cos%5E2%28x%29%29%5E7
= %281-cos%5E2%28x%29%29%5E4%2B%28cos%5E2%28x%29%29%5E7
Now let w+=+cos%5E2%28x%29. ===> +0%3C=+w+%3C=+1, and
===> %281-cos%5E2%28x%29%29%5E4%2B%28cos%5E2%28x%29%29%5E7+=+w%5E7+%2B+%281-w%29%5E4.
Let z+=+w%5E7+%2B+%281-w%29%5E4.
===> dz%2Fdw+=+7w%5E6+-+4%281-w%29%5E3. Letting this equal to zero, we get
7w%5E6+=+4%281-w%29%5E3.
===> root%283%2C+7%29%2Aw%5E2+=+root%283%2C4%29%2A%281-w%29, after taking cube root of both sides.
===> root%283%2C+7%29%2Aw%5E2+%2B+root%283%2C4%29%2Aw+-+root%283%2C4%29+=+0%29.
===>
= , since +0+%3C=+w+%3C=+1.
≈ 0.5860760201.

Now to the left of 0.5860760201, z' < 0, so z is decreasing on [0, 0.5860760201).
To the right of 0.5860760201, z' > 0, so z is increasing on (0.5860760201,1].

Hence there is a local minimum at w = 0.5860760201.
We only need to check the other critical points where the derivative doesn't exist, namely at w = 0 and w = 1,
to determine the other possible extrema.
At w = 0, z = 1.
At w = 1, z = 1.

Therefore the maximum of sin%5E8%28x%29%2Bcos%5E14%28x%29 is highlight%281%29, while the minimum is
0.5860760201%5E7+%2B+%281-0.5860760201%29%5E4+=+highlight%280.05310578625%29, approximately.

Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.
Please find the minimum and maximum values of the expression sin%5E8%28x%29%2Bcos%5E14%28x%29.
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Plots y = sin%5E8%28x%29%2Bcos%5E14%28x%29 (red) and y = x%5E7%2B%281-x%29%5E4 (green)


I am sending these plots to attention of the tutor "robertb" to show
that the minimum of z = w%5E7+%2B+%281-w%29%5E4 is slightly shifted from the minimum of sin%5E8%28x%29%2Bcos%5E14%28x%29.