SOLUTION: aaaaahhhh, please help me i have tried and tried and i just can't find the answer to this proplem......... if 3(x-6)=3x-18, then 3(x-7)=3x- ? do you know what ? should be??

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: aaaaahhhh, please help me i have tried and tried and i just can't find the answer to this proplem......... if 3(x-6)=3x-18, then 3(x-7)=3x- ? do you know what ? should be??      Log On


   

Question 104709: aaaaahhhh, please help me i have tried and tried and i just can't find the answer to this proplem.........
if 3(x-6)=3x-18, then 3(x-7)=3x- ?
do you know what ? should be??
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
3%28x-7%29 Start with the given expression


3%2Ax-3%2A7 Distribute 3 to each term in the parenthesis. In other words, multiply 3 by x and by -7


3x-21 Multiply -3 and 7 to get -21


So 3%28x-7%29=3x-21

note: in the previous problem 3%28x-6%29=3x-18 notice that 3 is multiplied by x and -6 to get 3x and -18