Question 1047053: Slot machines are now video games, with outcomes determined by random number generators. In the old days, slot machines were like this: you pull the lever to spin three wheels; each wheel has 20 symbols, all equally likely to show when the wheel stops spinning; the three wheels are independent of each other. Suppose that the middle wheel has 10 cherries among its 20 symbols, and the left and right wheels have one cherry each.
A). There are three ways that the three wheels can show two cherries and one symbol other than a cherry. Find the probability of each of these ways. (Use 4 decimal places.)
other symbol on right wheel =
other symbol on left wheel =
ther symbol on middle wheel =
(B) What is the probability that the wheels stop with exactly two cherries showing among them? (Use 3 decimal places.)
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! The three ways for two cherries are wheels 12,13,23
12 and 23 have equal probabilities and they are 0.05^0.50*0.95 (the 0.95 is probability of no cherry on last for wheel 12)=0.0238
wheel 13 has probability 0.05*0.50*0.05=0.000125;0.0001
Exactly two is the sum or 0.047 (rounded at end)
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