SOLUTION: factor each polynomial completely -4w^3 - 16w^2 + 20w

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Question 104688: factor each polynomial completely
-4w^3 - 16w^2 + 20w

Found 2 solutions by TP, Fombitz:
Answer by TP(29) About Me  (Show Source):
You can put this solution on YOUR website!
Looking at the polynomial we can see that 4w is a COMMON FACTOR and so
-4w^3 - 16w^2 + 20w = 4w[-w^2 - 4w + 5]
= -4w[w^2 + 4w - 5]
Now to factorise w^2 + 4w - 5 we need to look for two numbers that when added together give you 4 and when multiplied together give you -5.
These numbers are 5 and -1.
So -4w[w^2 + 4w - 5] = -4w[(w + 5)(w-1)]ANS

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
-4w%5E3+-+16w%5E2+%2B+20w
-4w%28w%5E2%2B4w-5%29 Factor out (-4w) from all terms.
-4w%28w%2B5%29%28w-1%29 Factor the quadratic equation.