SOLUTION: A boat traveled downstream a distance of 65 mi and then came right back. If the speed of the current was 20 mph and the total trip took 4 hours and 20 minutes, find the average sp

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Question 1046878: A boat traveled downstream a distance of 65 mi and then came right back. If the speed of the current was 20 mph and the total trip took 4 hours and 20 minutes, find the average speed of the boat relative to the water.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +s+ = the speed of the boat in still water ( no current )
Let +t+ = time to go downstream in hrs
+13%2F3+-+t+ = time to go upstream in hrs
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Equation for going downstream:
(1) +65+=+%28+s+%2B+20+%29%2At+
Equation for going upstream:
(2) +65+=+%28+s+-+20+%29%2A%28+13%2F3+-+t+%29+
------------------------------------
+65+=+%2813%2F3%29%2As+-+260%2F3+-+s%2At+%2B+20t+
+195+=+13s+-+260+-+3s%2At+%2B+60t+
+3s%2At+-+60t+=+13s+-+455+
+t%2A%28+3s+-+60+%29+=+13s+-+455+
Substitute (1) into this equation
+t+=+%28+13s+-+455+%29+%2F+%28+3s+-+60+%29+
+65+%2F+%28+s+%2B+20+%29+=+%28+13s+-+455+%29+%2F+%28+3s+-+60+%29+
+65%2A%28+3s+-+60+%29+=+%28+13s+-+455+%29%2A%28+s+%2B+20+%29+
+195s+-+3900+=+13s%5E2+-+455s+%2B+260s+-+9100+
+13s%5E2+-195s+-+195s+-+5200+=+0+
+13s%5E2+-+390s+-+5200+=+0+
+s%5E2+-+30s+-+400+=+0+
+%28+s+-+40+%29%2A%28+s+%2B+10+%29+=+0+
+s+=+40+
The average speed of the boat is still water is
40 mi/hr
--------------
check:
(1) +65+=+%28+s+%2B+20+%29%2At+
(1) +t+=+65%2F%28+s+%2B+20+%29+
(1) +t+=+65%2F60+
(1) +t+=+13%2F12+
and
(2) +65+=+%28+s+-+20+%29%2A%28+13%2F3+-+t+%29+
(2) +65+=+%28+40+-+20+%29%2A%28+52%2F12+-+13%2F12+%29+
(2) +65+=+20%2A%28+39%2F12+%29+
(2) +12%2A65+=+20%2A39+
(2) +780+=+780+
Ok