Question 1046836: ⦁ A truck has a shipment of 300 I-phones. If there are 4 defective I-phones on the truck, what is the probability of picking 20 I-phones at random and getting
⦁ Exactly one defective I-phone?
⦁ Exactly two defective I-phones?
⦁ Exactly three defective I-phones?
⦁ Exactly four defective I-phones?
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website! p = 4/300 = 1/75 = .0133
n = 20
TI syntax for P(x-value) is binompdf(n, p, x-value).
⦁ Exactly one defective I-phone? p = binompdf(20, .0133, 1) = .2062
⦁ Exactly two defective I-phones? p = binompdf(20, .0133, 2) = .2064
⦁ Exactly three defective I-phones? p = binompdf(20, .0133, 3)= .0023
⦁ Exactly four defective I-phones? p = p = binompdf(20, .0133, 4)= .0001
Recommend Using stattrek.com to check Results
until You are familiar with Using Your Calculator.
One could also Use Your Casio fx-115 ES plus 0r fx-991 ES plus
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