SOLUTION: find two consecutive odd integers whose product is 39 more than three times their sum

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Question 1046810: find two consecutive odd integers whose product is 39 more than three times their sum
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let the consecutive odd integers be +n+ and +n+%2B+2
+n%2A%28+n+%2B+2+%29+=+3%2A%28+n+%2B+n+%2B+2+%29+%2B+39+
+n%5E2+%2B+2n+=+6n+%2B+6+%2B+39+
+n%5E2+-+4n+-+45+=+0+
+%28+n+-+9+%29%2A%28+n+%2B+5+%29+=+0+
+n+=+9+ ( this is the positive choice )
and
+n+%2B+2+=+11+
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The integers are 9 and 11
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check:
+n%2A%28+n+%2B+2+%29+=+3%2A%28+n+%2B+n+%2B+2+%29+%2B+39+
+9%2A%28+9+%2B+2+%29+=+3%2A%28+9+%2B+9+%2B+2+%29+%2B+39+
+9%2A11+=+3%2A20+%2B+39+
+99+=+60+%2B+39+
+99+=+99+
OK