Question 1046785: suppose you have $6 in nickles, dimes, and quarters. if you have twice as many nickels as quarters and the total value of your dimes is the same as the total value of your quarters, how many coins do you have in total
Answer by ikleyn(52756)   (Show Source):
You can put this solution on YOUR website! .
suppose you have $6 in nickles, dimes, and quarters. if you have twice as many nickels as quarters and the total value of your dimes
is the same as the total value of your quarters, how many coins do you have in total
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Let "x" be the number of quarters.
Then the number of nickels is 2x, and the number of dimes is 2.5x.
So, you have 5*(2x) cents in nickels,
2.5*10*x = 25x cents in dimes, and
25*x cents in quarters.
In all, you have 10x + 25x + 25x = 60x cents in coins.
According to the condition, it is $6 = 600 cents. So, your equation is
60x = 600, or x =  = 10.
You have 10 quarters, 25 dimes and 20 nickels.
Check. 10*25 + 25*10 + 20*5 = 600 cents = $6.00
Answer. 10 + 25 + 20 = 55 coins, in all.
There is entire bunch of the lessons on coin problems
- Coin problems
- More Coin problems
- Solving coin problems without using equations
- Kevin and Randy Muise have a jar containing coins
- Typical coin problems from the archive
- More complicated coin problems
- OVERVIEW of lessons on coin word problems
in this site.
Read them and become an expert in solution of coin problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
It contains many other solved word problems, as well as many other interesting and useful things.
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