SOLUTION: There are consecutive integers such that the sum of the first, twice the second and seven more than the third is 47. what are the numbers?

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Question 1046733: There are consecutive integers such that the sum of the first, twice the second and seven more than the third is 47. what are the numbers?
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
n%2B2%28n%2B1%29%2B7%2B%28n%2B2%29=47, the exact translation into an equation, n for the first consecutive INTEGER.

4n%2B2%2B7%2B2=47

4n%2B4=40

n%2B1=10

highlight%28n=9%29