Question 1046632: A basket ball player makes 70% of her free throws. She takes 7 free throws in a game, and makes 5 of her 7 throws. If the shots are independent of each other, Then the probability that she makes the first five and misses the last 2 is about
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A basket ball player makes 70% of her free throws. She takes 7 free throws in a game, and makes 5 of her 7 throws. If the shots are independent of each other, Then the probability that she makes the first five and misses the last 2 is about
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This is a binomial problem with n = 7 and p = 0.7
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P(x = 5) = 7C5*0.7^5*0.3^2 = binompdf(7,0.7.5) = 0.3177
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Cheers,
Stan H.
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