Question 1046624: There is a collection of nickels, dimes, and quarters with total value of $47.60. There are 28 more dimes than nickels. There are 5 times as many quarters as dimes. How many quarters are in the collection?
Found 2 solutions by ikleyn, ewatrrr: Answer by ikleyn(52775) (Show Source):
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There is a collection of nickels, dimes, and quarters with total value of $47.60.
There are 28 more dimes than nickels. There are 5 times as many quarters as dimes.
How many quarters are in the collection?
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Let "d" be the number of dimes.
Then the number of quarters is 5d,
and the number of nickels is d-28, according to the condition.
Hence, the total in cents is
10d + 25*(5d) + 5*(d-28) = 4760, or
10d + 125d + 5d - 140 = 4760, or
140d = 4760 + 140,
d = = 35.
So, there are 35 dimes in the collection.
Then the number of quarters is 5*35 = 175 and the number of nickels is 35 - 28 = 7.
Check. 5*7 + 10*35 + 25*175 = 4760. Correct !
Answer. 7 nickels, 35 dimes and 175 quarters.
There is a bunch of my lessons on coin problems
- Coin problems
- More Coin problems
- Solving coin problems without using equations
- Kevin and Randy Muise have a jar containing coins
- Typical coin problems from the archive
in this site.
Read them and become an expert in counting coins.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
which contains many other word problems and many other interesting anf useful things.
Answer by ewatrrr(24785) (Show Source):
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