SOLUTION: please help me solve this problem : area of ABC is 60 and < ABC=< ACB, also BC=10, what is the perimeter of the triangle?

Algebra ->  Triangles -> SOLUTION: please help me solve this problem : area of ABC is 60 and < ABC=< ACB, also BC=10, what is the perimeter of the triangle?      Log On


   

Question 1046503: please help me solve this problem : area of ABC is 60 and < ABC=< ACB, also BC=10, what is the perimeter of the triangle?
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Since angle ABC is equal to Angle ACB, the triangle is isosceles. Side BC is the base that measures 10, and since the area is 60, the height must be





Since the triangle is isosceles, the altitude is a perpendicular bisector of the base and therefore divides the triangle into two congruent right triangles with legs that measure 12 and 5.

Using Pythagoras, you can calculate the measure of each of the equal sides of the original triangle, and then the perimeter is just the sum of the measures of the three sides.

.

John

My calculator said it, I believe it, that settles it