Question 1046419: Three two-digit numbers have consecutive tens digits and have units digit all equal to 5. If the tens digit of the smallest number is n, what is the sum of three numbers?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! The numbers are n5, (n+1)5, and (n+2)5
The sum is (n+n+1+n+2+1)5=(3n+4)5, the 1 being from adding 3 numbers that end in 5. We get 15, and there is a 1 in the tens column.
Check with 25,35,45
n=2 in this instance
(3n+4)=10
The number should be 105.
25+35+45=105
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