SOLUTION: one third of the third of three consecutive even integers is four less than half the first .find the first integer.

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Question 1046390: one third of the third of three consecutive even integers is four less than half the first .find the first integer.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39631) About Me  (Show Source):
You can put this solution on YOUR website!
First integer, 2n.
the third integer, 2n%2B4.

%281%2F3%29%282n%2B4%29=-4%2B%281%2F2%29%282n%29

Answer by MathTherapy(10558) About Me  (Show Source):
You can put this solution on YOUR website!

one third of the third of three consecutive even integers is four less than half the first .find the first integer.
Let smallest integer be S

Then 2nd and 3rd = S + 2, and S + 4, respectively

We then get: %281%2F3%29%28S+%2B+4%29+=+%281%2F2%29S+-+4

%28S+%2B+4%29%2F3+=+S%2F2+-+4

2(S + 4) = 3S - 24 ------ Multiplying by LCD, 6

2S + 8 = 3S - 24

2S - 3S = - 24 - 8

- S = - 32

S. or smallest (first) integer = highlight_green%28matrix%281%2C3%2C+%28-+32%29%2F%28-+1%29%2C+or%2C+32%29%29

It is that SIMPLE....nothing complex!