SOLUTION: find three consecutive odd integers that sum of two times the first, three times the second, and one times the third is -428

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Question 1046347: find three consecutive odd integers that sum of two times the first, three times the second, and one times the third is -428
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Let x,%28x%2B2%29,%28x%2B4%29 represent the three consecutive odd integers
two times the first is 2x
three times the second is 3%28x%2B2%29
if two times the first, three times the second, and one times the third is -428, we have
2x%2B3%28x%2B2%29%2B%28x%2B4%29=+-428
2x%2B3x%2B6%2Bx%2B4=-428
6x%2B10=-428
6x=-428-10
6x=-438
x=-438%2F6
x=-73-> first odd integer
%28x%2B2%29->%28-73%2B2%29->-71->second odd integer
%28x%2B4%29->%28-73%2B4%29->-69->third odd integer

check their sum:
two times the first is 2%28-73%29=-146
three times the second is 3%28-71%29=-213
and third one is -69
%28-146%29%2B%28-213%29%2B%28-69%29=-428
-428=-428