SOLUTION: Find the perimeter if the basketball court if the width is x+5 over x+1 and the length is x+3 over x. The length of a rectangle in terms of X is x^2 - 2x - 8 over x-5 and the w

Algebra ->  Rational-functions -> SOLUTION: Find the perimeter if the basketball court if the width is x+5 over x+1 and the length is x+3 over x. The length of a rectangle in terms of X is x^2 - 2x - 8 over x-5 and the w      Log On


   

Question 1046338: Find the perimeter if the basketball court if the width is x+5 over x+1 and the length is x+3 over x.
The length of a rectangle in terms of X is x^2 - 2x - 8 over x-5 and the width of the rectangle is x^2-7x+10. What is the area of the rectangle in terms of X? Leave your answer in factored form.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
if the width is W=%28x%2B5%29%2F%28x%2B1%29 and the length is L=%28x%2B3%29%2Fx,
the perimeter if the basketball court will be
P=2%28W%2BL%29
P=2%28%28x%2B5%29%2F%28x%2B1%29%2B%28x%2B3%29+%2Fx%29

P=2%28x%28x%2B5%29%2B%28x%2B3%29+%28x%2B1%29%29%2F%28%28x%2B1%29x%29%29

The length of a rectangle in terms of X is %28x%5E2+-+2x+-+8%29%2F+%28x-5%29+and the width of the rectangle is %28x%5E2-7x%2B10%29.
the area of the rectangle in terms of X:
A=%28%28x%5E2+-+2x+-+8%29%2F+%28x-5%29+%29%28x%5E2-7x%2B10%29
A=%28%28x%2B2%29+%28x-4%29%2F+cross%28x-5%29+%29++%28%28x-2%29cross%28+%28x-5%29%29%29
A=%28x%2B2%29+%28x-4%29+%28x-2%29