SOLUTION: Prove the statement using the &#949;, &#948; definition of a limit. lim x^2=0 x&#8594;0 Given &#949; > 0, we need &#948; > 0 such that if 0 < |x &#8722; 0| < &#8201;&#948;

Algebra ->  Functions -> SOLUTION: Prove the statement using the &#949;, &#948; definition of a limit. lim x^2=0 x&#8594;0 Given &#949; > 0, we need &#948; > 0 such that if 0 < |x &#8722; 0| < &#8201;&#948;      Log On


   



Question 1046280: Prove the statement using the ε, δ definition of a limit.
lim x^2=0
x→0
Given ε > 0, we need δ > 0 such that if 0 < |x − 0| <  δ, then |x2 − 0| <  ε⇔ ____________ <  ε ⇔
|x| < _____________. Take δ = ____________.Then 0 < |x − 0| <  δ right double arrow implies
|x2 − 0| < ε. Thus,
lim
x→0 x^2 = 0 by the definition of a limit.

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
1st blank: abs%28x%5E2%29, or abs%28x%29%5E2

2nd blank: sqrt%28epsilon%29

3rd blank: sqrt%28epsilon%29