SOLUTION: The dimensions of Peyton and Parker's sandbox are t^2m by t^5m by 3v^2m. One cubic meter of the sandbox contains 3s^21 grains of sand. How many grains of sand are in the sandbox.

Algebra ->  Expressions-with-variables -> SOLUTION: The dimensions of Peyton and Parker's sandbox are t^2m by t^5m by 3v^2m. One cubic meter of the sandbox contains 3s^21 grains of sand. How many grains of sand are in the sandbox.       Log On


   



Question 1046152: The dimensions of Peyton and Parker's sandbox are t^2m by t^5m by 3v^2m. One cubic meter of the sandbox contains 3s^21 grains of sand. How many grains of sand are in the sandbox.
A. 27t^10 v^2 s^21
B. t^10 v^2 s^21
C. 3t^7 v^2 s^21
D. 9t^7 v^2 s^21

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

%28t%5E2+%2A+t%5E5+%2A+3v%5E2%293s%5E21=%283t%5E7v%5E2%293s%5E21=9t%5E7v%5E2s%5E21
so, answer is D.