SOLUTION: Two numbers differ by 40 when each is increased by 8 the bigger number is thrice lesser the lesser numberif one number is x then find the other

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Question 1046082: Two numbers differ by 40 when each is increased by 8 the bigger number is thrice lesser the lesser numberif one number is x then find the other

Found 2 solutions by dkppathak, MathTherapy:
Answer by dkppathak(439) About Me  (Show Source):
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Two numbers differ by 40 when each is increased by 8 the bigger number is thrice lesser the lesser numberif one number is x then find the other
let one number is x and other is 40-x
both number increase 8
than number will be x +8 other will be 40-x+8=48-x
as per given conditions
48-x=3x-x
48-x=2x
48=2x+x
3x=48
x=16 other number 24

Answer by MathTherapy(10556) About Me  (Show Source):
You can put this solution on YOUR website!
Two numbers differ by 40 when each is increased by 8 the bigger number is thrice lesser the lesser numberif one number is x then find the other
If the smaller number is x, then the larger number is: x + 40

If the larger number is x, then the smaller number is: x - 40

Going further, we can say that: