SOLUTION: the triangle has 6m,8m and 10m .what is the angel formen by the intersection of the two shortest sides?

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Question 1045998: the triangle has 6m,8m and 10m .what is the angel formen by the intersection of the two shortest sides?

Found 2 solutions by jim_thompson5910, MathTherapy:
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!
The smallest two sides are 6 m and 8 m. The angle between them is opposite the side 10 m.

Law of Cosines

c^2 = a^2 + b^2 - 2*a*b*cos(C)

10^2 = 6^2 + 8^2 - 2*6*8*cos(C)

100 = 36 + 64 - 96*cos(C)

100 = 100 - 96*cos(C)

100 - 100 = 100 - 96*cos(C) - 100

0 = -96*cos(C)

-96*cos(C) = 0

cos(C) = 0

C = 90 degrees

The final answer is 90 degrees.

Answer by MathTherapy(10557) (Show Source):
You can put this solution on YOUR website!

the triangle has 6m,8m and 10m .what is the angel formen by the intersection of the two shortest sides?

If you divide each side by 2, you get a 3-4-5 right-triangle.
Where the 2 shortest sides intersect is the right angle, or