SOLUTION: find the standard equation of the line which passes through (1,-3) and is perpendicular to the line defined by 2y=3x-1

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Question 1045941: find the standard equation of the line which passes through (1,-3) and is perpendicular to the line defined by 2y=3x-1
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
2y=3x-1
finding the Slope
the standard slope-intercept form for an equation of a line is y+=+highlight_green%28m%29x+%2B+highlight%28b%29
where m is the slope and b the y-intercept.
2y=3x-1
Solving for y
y =-(3/2)x +1/2 Green Line
m = -3/2
Slope of Line perpendicular is 2/3 (negative reciprocal)
***Using point-slope form, y+-+y%5B1%5D+=+highlight_green%28m%29%28x+-+x%5B1%5D%29
y +3 = (2/3)( x - 1) Pt (1,-3) on this perpendicular line
y = (2/3)x -2/3 - 9/3
y = (2/3)x - 11/3 Blue Line