SOLUTION: find the center and radius of the circle defined by x^2-6x+1=8y-y^2

Algebra ->  Coordinate-system -> SOLUTION: find the center and radius of the circle defined by x^2-6x+1=8y-y^2      Log On


   



Question 1045937: find the center and radius of the circle defined by x^2-6x+1=8y-y^2
Found 2 solutions by Fombitz, ikleyn:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square in x and y to get to general equation.
x%5E2-6x%2B1%2By%5E2-8y=0
%28x%5E2-6x%2B9%29%2B1%2B%28y%5E2-8y%2B16%29=9%2B16
%28x-3%29%5E2%2B%28y-4%29%5E2=24
Center : (3,4)
Radius : R=sqrt%2824%29=2sqrt%286%29

Answer by ikleyn(52781) About Me  (Show Source):