SOLUTION: Solve the inequality and express the solution in terms of intervals whenever possible. (I forgot how to get common denominator) (1/x-2) >= (3/x+1) (1/x-2) – (3/x+1) >=0

Algebra ->  Inequalities -> SOLUTION: Solve the inequality and express the solution in terms of intervals whenever possible. (I forgot how to get common denominator) (1/x-2) >= (3/x+1) (1/x-2) – (3/x+1) >=0      Log On


   

Question 1045845: Solve the inequality and express the solution in terms of intervals whenever possible. (I forgot how to get common denominator)
(1/x-2) >= (3/x+1)
(1/x-2) – (3/x+1) >=0
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!

<===> %28-2x%2B7%29%2F%28%28x-2%29%28x%2B1%29%29+%3E=+0++.
===> The critical values of this inequality are -1, 2, and 7/2.
The expression %28-2x%2B7%29%2F%28%28x-2%29%28x%2B1%29%29+ is
--non-negative over (-infinity, -1);
--negative over (-1,2);
--non-negative over (2,7/2];
--negative over (7/2, infinity).
Therefore the solution set is (-infinity, -1)∪(2,7/2].