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In quadrilateral WXYZ, XZ bisects WXY and WZY. Prove that XWZ = XYZ.
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From the condition, the sum of two angles, WXZ and WZX, of the triangle WXZ
is equal to the sum of two angles, ZXY and XZY, of the triangle XYZ.
Since the sum of two angles of one triangle equals the sum of two angles of the other triangle, the third angles of the triangles are congruent.
Proved.