You can put this solution on YOUR website! ..........(1) ..........(2) ..........(3)
start with first two equations
..........(1) ..........(2)
--------------------------------add
......solve for ................(1a)
go to
..........(2)......both sides multiply by ..........(3)
----------------------------- ..........(2) ..........(3)
--------------------------------------add
......solve for ................(1b)
from 1a and 1b we have
..................solve for
now we can find ................(1b)
now, go to ..........(1), substitute and and solve for
so, your solutions are: