SOLUTION: What is the equation of a line that is perpendicular to y = 4x - 2 and goes through (4, 4) ? A.) y = -4x + 1 B.) y = ¼x + 3 C.) y = -¼x + 4 D.) y = -¼x + 5

Algebra ->  Test -> SOLUTION: What is the equation of a line that is perpendicular to y = 4x - 2 and goes through (4, 4) ? A.) y = -4x + 1 B.) y = ¼x + 3 C.) y = -¼x + 4 D.) y = -¼x + 5       Log On


   

Question 1045677: What is the equation of a line that is perpendicular to y = 4x - 2 and goes through (4, 4) ?
A.) y = -4x + 1
B.) y = ¼x + 3
C.) y = -¼x + 4
D.) y = -¼x + 5
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Perpendicular lines have slopes that are negative reciprocals.
m%5B1%5D%2Am%5B2%5D=-1
4%2Am%5B2%5D=-1
m%5B2%5D=-1%2F4
Now using the point slope form,
y-4=-%281%2F4%29%28x-4%29
y-4=-%281%2F4%29x%2B1
y=-%281%2F4%29x%2B5
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