SOLUTION: What is the equation of the axis of parabola y^2-4y+12x-32=0?

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Question 1045660: What is the equation of the axis of parabola y^2-4y+12x-32=0?
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52818) About Me  (Show Source):
Answer by MathTherapy(10555) About Me  (Show Source):
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What is the equation of the axis of parabola y^2-4y+12x-32=0?
12x+=+-+y%5E2+%2B+4y+%2B+32

x+=+%28-+1%2F12%29y%5E2+%2B+%284%2F12%29y+%2B+%2832%2F12%29

x+=+%28-+1%2F12%29y%5E2+%2B+%281%2F3%29y+%2B+%288%2F3%29	

Axis of symmetry: