SOLUTION: Determine the axis of parabola x^2-2x+8y+25=0.

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Question 1045659: Determine the axis of parabola x^2-2x+8y+25=0.
Found 2 solutions by ikleyn, ewatrrr:
Answer by ikleyn(52884) About Me  (Show Source):
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
parabola x^2-2x+8y+25=0
8y = x^2-2x+25
completing the square on the left side of the EQ
8y = (x-1)^2 -1 + 25
8y = (x-1)^2 + 24
y = (1/8)(x-1)^2 + 3 Vertex(1,3)
Axis: x= 1

Need to Know____________
The vertex form of a Parabola opening up(a>0) or down(a<0),
y=a%28x-h%29%5E2+%2Bk
where(h,k) is the vertex and x = h is the Line of Symmetry ,
the focus is (h,k + p), With Directrix y = (k - p), a = 1/(4p)